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Solve : PCM bandwidth?

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im working on a question and I came up with an answer, but i would just like to clarify if its correct

the question asks We sample and digitize (with PCM) a VOICE signal with fmax=4 kHz and we use nb=6 bits/sample. The digital signal must be transmitted on a channel with bandwidth Bch= 6 kHz. What is the number of bits PER signal ELEMENT (R=?) for the worst case factor c=1 ?

the answer i have is r=4bits

I used the formula
B(min) = c(N)(1/r) = c(n(sub b))(f(sub s))(1/r) = c(n(sub b))(2)(B analog)(1/r)
As I said in one of your other posts, We PREFER not to help with homework here. Sorry.



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