1.

solve please correct are you there ​

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Answer:

\huge\mathtt\purple{<klux>X</klux> = 3 ; y = 2}

Explanation:

3x - y = 7 - (i)

x + 4y = 11 - (ii)

Firstly taken (i)

3x - y = 7

3x = 7+y

x =  \frac{7 + y}{3}  \:  \:  \:  \:  \:  - (iii)

PUT VALUE of x (iii) in (ii)

x + 4y = 11

\frac{7 + y}{3}  + 4y = 11( Take LCM )

\frac{7 + y + 12y}{3}  = 11

\frac{7 + 13y}{3}  = 11

7 + 13y = 11 \times 3

7 + 13y = 33

13y = 33 - 7 = 26

13y  = 26

y =  \frac{26}{13}

y = 2

Now, put the value of y in (iii)

x =  \frac{7 + y}{3}

x =  \frac{7 + 2}{3}

x =   \frac{9}{3}

x = 3

\large\mathbb\red{x = 3 ; y = 2}

\huge\mathcal\pink{Hope \:  it \:  helps  \: you!}



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