solve please correct are you there

1.	solve please correct are you there
Answer» Answer: $\huge\mathtt\purple{<klux>X</klux> = 3 ; y = 2}$ Explanation: 3x - y = 7 - (i) x + 4y = 11 - (ii) Firstly taken (i) 3x - y = 7 3x = 7+y $x = \frac{7 + y}{3} \: \: \: \: \: - (iii)$ PUT VALUE of x (iii) in (ii) x + 4y = 11 $\frac{7 + y}{3} + 4y = 11$ ( Take LCM ) $\frac{7 + y + 12y}{3} = 11$ $\frac{7 + 13y}{3} = 11$ $7 + 13y = 11 \times 3$ $7 + 13y = 33$ $13y = 33 - 7 = 26$ $13y = 26$ $y = \frac{26}{13}$ $y = 2$ Now, put the value of y in (iii) $x = \frac{7 + y}{3}$ $x = \frac{7 + 2}{3}$ $x = \frac{9}{3}$ $x = 3$ $\large\mathbb\red{x = 3 ; y = 2}$ $\huge\mathcal\pink{Hope \: it \: helps \: you!}$

Answer»

Answer:

$\huge\mathtt\purple{<klux>X</klux> = 3 ; y = 2}$