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Solve ∫ sec2 x cosec2 x dx on I ⊂ R [{nπ : n ∈ Z} ∪ {(2n + 1) (π/2) : n ∈ Z}] |
Answer» ∫ sec2 x.cosec2 x dx = ∫ (1/(cos2 x sin2 x)) dx = ∫ (sin2 x + cos2 x/(cos2 x.sin2 x)) dx = ∫ (1/cos2 x) dx + ∫ (1/sin2 x) dx = ∫ sec2 x dx + ∫ cosec2 x dx = tan x – cot x + C |
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