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Solve : sin-1 2a/(1 + a2) + cos-1 (1 - b2)/(1 + b2) = 2tan-1 x |
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Answer» Since, sin-1 2a/(1 + a2) = 2tan-1 a and cos-1 (1 - b2)/(1 + b2) = 2tan-1 b ∴ given problem can be written as tan-1 a + tan-1 b = tan-1 x tan-1 (a + b)/(1 - ab) = tan-1 x ∴ x = (a - b)/(1 - ab) |
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