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                                    Solve the cryptarithm:`B A x B3 5 7A` | 
                            
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Answer» `BAxxB3 = 57A` If we multiply any number `x` with 3 and we get a number `x` in unit digit, then `x` is either `5` or `0`. So, in the given question, `A` can be `5` or `0`. If, `A` is `5`, then, the result is `575`. Then, `3**B+1` can be `7`. So, `B` can be `2`. If we try `A=3` and `B=2`, it satisfies our multiplication. So, this is the right answer.  | 
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