Solve the Differential Equation by Variation of Parameters:y'' − 4y

1.	Solve the Differential Equation by Variation of Parameters:y'' − 4y = 4xe2x
Answer» The general solution of differential equationy'' − 4y = 4xe^2xisy =c\(_1\)e^2x+ c\(_2\)e^-2x+ (x²/2)e^2x- 4xe^2x+ 16e^2x We will be solving this by finding thehomogeneous andcomplementary solutions of the equation.

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