Solve the equation 13( y – 4) – 3(y-9) – 5(y + 4) = 0. Check you

1.	Solve the equation 13( y – 4) – 3(y-9) – 5(y + 4) = 0. Check your result.
Answer» The above question can be written as,= 13y – 52 – 3y + 27 – 5y – 20 = 0 Now, find the value of y by considering the above equation, = 13y – 3y – 5y – 52 + 27 – 20 = 0 = 13y – 8y – 72 + 27 = 0 = 5y – 45 = 0 Transposing -45 to RHS and it becomes 45 = 5y = 45 Multiplying both side by (1/5) = 5y × (1/5) = 45 × (1/5) = y = 9 By substituting 9 in the place of y in given equation, we get LHS, = 5y – 45 = 5 × (9) – 45 = 45 – 45 = 0 RHS, = 0 By comparing LHS and RHS = 0 = 0 ∴ LHS = RHS Hence, the result is verified.

Solve the equation 13( y – 4) – 3(y-9) – 5(y + 4) = 0. Check your result.

Answer»

The above question can be written as,= 13y – 52 – 3y + 27 – 5y – 20 = 0

Now, find the value of y by considering the above equation,

= 13y – 3y – 5y – 52 + 27 – 20 = 0

= 13y – 8y – 72 + 27 = 0

= 5y – 45 = 0

Transposing -45 to RHS and it becomes 45

= 5y = 45

Multiplying both side by (1/5)

= 5y × (1/5) = 45 × (1/5)

= y = 9

By substituting 9 in the place of y in given equation, we get

LHS,

= 5y – 45

= 5 × (9) – 45

= 45 – 45

= 0

RHS,

= 0

By comparing LHS and RHS

= 0 = 0

∴ LHS = RHS

Hence, the result is verified.