Solve the equation (2/3)x = (3/8)x + (7/12). Check your result.

1.	Solve the equation (2/3)x = (3/8)x + (7/12). Check your result.
Answer» Find the value of x by considering the above equation,Transposing (3/8)x to RHS and it becomes -(3/8)x. = (2/3)x – (3/8)x = (7/12) = [(16 – 9) / 24]x = (7/12) = (7/24) x = (7/12) Multiplying both side by (24/7), = (7/24)x × (24/7) = (7/12) × (24/7) = x = 2 By substituting 2 in the place of x in given equation, we get LHS, = (2/3)x = (2/3) × (2) = (4/3) RHS, = (3/8)x + (7/12) = (3/8) × (2) + (7/12) = (3/4) + (7/12) = (9 + 7) / (12) = (16/12) = (4/3) By comparing LHS and RHS = (4/3) = (4/3) ∴ LHS = RHS Hence, the result is verified.

Answer»

Find the value of x by considering the above equation,Transposing (3/8)x to RHS and it becomes -(3/8)x.

= (2/3)x – (3/8)x = (7/12)

= [(16 – 9) / 24]x = (7/12)

= (7/24) x = (7/12)

Multiplying both side by (24/7),

= (7/24)x × (24/7) = (7/12) × (24/7)

= x = 2

By substituting 2 in the place of x in given equation, we get

LHS,

= (2/3)x

= (2/3) × (2)

= (4/3)

RHS,

= (3/8)x + (7/12)

= (3/8) × (2) + (7/12)

= (3/4) + (7/12)

= (9 + 7) / (12)

= (16/12)

= (4/3)

By comparing LHS and RHS

= (4/3) = (4/3)

∴ LHS = RHS

Hence, the result is verified.

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