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Solve the equation 2 (x – 2) + 3 (4x – 1) = 0. Check your result. |
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Answer» The above question can be written as,= 2x – 4 + 12x – 3 = 0 Now, find the value of x by considering the above equation, = 2x + 12x – 4 – 3 = 0 = 14x – 7 = 0 Transposing -7 to RHS and it becomes 7 = 14x = 7 Multiplying both side by (1/14) = 14x × (1/14) = 7 × (1/14) = x = (7/14) = x = 1/2 By substituting 1/2 in the place of x in given equation, we get LHS, = (2 × (1/2)) – 4 + (12 × (1/2)) – 3 = 1– 4 + 6 – 3 = 7 – 7 = 0 By comparing LHS and RHS = 0 = 0 ∴ LHS = RHS Hence, the result is verified. |
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