Solve the equation 2x – (1/3) = (1/5) – x. Check your result.

1.	Solve the equation 2x – (1/3) = (1/5) – x. Check your result.
Answer» Now, find the value of x by considering the given equation,= 2x – (1/3) = (1/5) – x Transposing – (1/3) to RHS and it becomes (1/3) and – x to LHS it becomes x = 2x + x = (1/5) + (1/3) = 3x = (3 + 5) / 15 = 3x = 8/15 Multiplying both side by (1/3) = 3x × (1/3) = (8/15) × (1/3) = x = (8/45) By substituting (8/45) in the place of x in given equation, we get LHS, = 2 × (8/45) – (1/3) = (16/45) – (1/3) = (16 – 15) / 45 = (1/45) RHS = (1/5) – (8/45) = (9-8) / 45 = (1/45) By comparing LHS and RHS = (1/45) = (1/45) ∴ LHS = RHS Hence, the result is verified.

Answer»

Now, find the value of x by considering the given equation,= 2x – (1/3) = (1/5) – x

Transposing – (1/3) to RHS and it becomes (1/3) and – x to LHS it becomes x

= 2x + x = (1/5) + (1/3)

= 3x = (3 + 5) / 15

= 3x = 8/15

Multiplying both side by (1/3)

= 3x × (1/3) = (8/15) × (1/3)

= x = (8/45)

By substituting (8/45) in the place of x in given equation, we get

LHS,

= 2 × (8/45) – (1/3)

= (16/45) – (1/3)

= (16 – 15) / 45

= (1/45)

RHS

= (1/5) – (8/45)

= (9-8) / 45

= (1/45)

By comparing LHS and RHS

= (1/45) = (1/45)

∴ LHS = RHS

Hence, the result is verified.

Discussion