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solve the equation 3x + 2y+ 2 = 0 , 5x - y - 27 = 0 |
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Answer» \(3x+2y+2=0...(1)\) \(5x- y-27=0...(2)\) Multiply equation (2) by (1), we get \(10x-2y-54=0...(3)\) By adding equations (1) and (3), we get \(13x-52=0\) \(\Rightarrow x =\frac{52}{13}=4\) put x = 4 in equation (1) , we get \(12+2y+2=0\) \(\Rightarrow 2y=-14\) \(\Rightarrow y=-7\) Hence, \(x = 4\) & \(y = -7\) is solutions of a given system of equations |
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