1.

solve the equation 3x + 2y+ 2 = 0 , 5x - y - 27 = 0

Answer»

\(3x+2y+2=0...(1)\)

\(5x- y-27=0...(2)\)

Multiply equation (2) by (1),  we get

\(10x-2y-54=0...(3)\)

By adding equations (1) and (3), we get

\(13x-52=0\)

\(\Rightarrow x =\frac{52}{13}=4\)

put  x = 4 in equation (1) , we get

\(12+2y+2=0\)

\(\Rightarrow 2y=-14\)

\(\Rightarrow y=-7\)

Hence, \(x = 4\) & \(y = -7\) is solutions of a given system of equations



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