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Solve the equation. Also, verify the result.(5x – 1)/3 – (2x – 2)/3 = 1 |
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Answer» Given (5x – 1)/3 – (2x – 2)/3 = 1 (5x – 1 – 2x – 2)/3 = 1 (3x + 1)/3 = 1 Multiplying both sides by 3 we get (3x + 1)/3 × 3 = 1 × 3 (3x + 1) = 3 Subtracting 1 from both sides we get 3x + 1 – 1 = 3 – 1 3x = 2 Dividing both sides by 3, we get 3x + 1 – 1 = 3 -1 3x = 2 Dividing both sides by 3, we get 3x/3 = 2/3 x = 2/3 Verification: Substituting x = 2/3 in LHS, we get (5 (2/3) – 1)/3 – (2 (2/3) – 2)/3 = 1 (10/3 -1)/3 – (4/3 – 2)/3 = 1 (7/3)/3 – (-2/3)/3 = 1 (7/9) + (2/9) = 1 (9/9) = 1 1 = 1 Thus LHS = RHS Hence, verified. |
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