Solve the equation. Also, verify the result.(x/2) = (x/3) + 1

1.	Solve the equation. Also, verify the result.(x/2) = (x/3) + 1
Answer» Given (x/2) = (x/3) + 1 Transposing (x/3) to LHS we get (x/2) – (x/3) = 1 (3x – 2x)/6 = 1 [LCM of 3 and 2 is 6] x/6 = 1 Multiplying 6 to both sides we get, x = 6 Verification: Substituting x = 6 in given equation we get (6/2) = (6/3) + 1 3 = 2 + 1 3 = 3 Thus LHS = RHS Hence, verified.

Answer»

Given (x/2) = (x/3) + 1

Transposing (x/3) to LHS we get

(x/2) – (x/3) = 1

(3x – 2x)/6 = 1 [LCM of 3 and 2 is 6]

x/6 = 1

Multiplying 6 to both sides we get,

x = 6

Verification:

Substituting x = 6 in given equation we get

(6/2) = (6/3) + 1

3 = 2 + 1

3 = 3

Thus LHS = RHS

Hence, verified.

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