Solve the equation and also check your results:(45-2x)/15 – (4x+10)

1.	Solve the equation and also check your results:(45-2x)/15 – (4x+10)/5 = (15-14x)/9
Answer» (45-2x)/15 – (4x+10)/5 = (15-14x)/9 By rearranging (45-2x)/15 – (4x+10)/5 – (15-14x)/9 = 0 By taking LCM for 15, 5 and 9 which is 45 ((45-2x)3 – (4x+10)9 – (15-14x)5)/45 = 0 (135 – 6x – 36x – 90 – 75 + 70x)/45 = 0 (28x – 30)/45 = 0 By cross-multiplying 28x – 30 = 0 28x = 30 x = 30/28 = 15/14 Let us verify the given equation now, (45-2x)/15 – (4x+10)/5 = (15-14x)/9 By substituting the value of ‘x’ we get, (45-2(15/14))/15 – (4(15/14) + 10)/5 = (15 – 14(15/14))/9 (45- 15/7)/15 – (30/7 + 10)/5 = (15-15)/9 300/105 – 100/35 = 0 (300-300)/105 = 0 0 = 0 Hence, the given equation is verified.

Solve the equation and also check your results:(45-2x)/15 – (4x+10)/5 = (15-14x)/9

Answer»

(45-2x)/15 – (4x+10)/5 = (15-14x)/9

By rearranging

(45-2x)/15 – (4x+10)/5 – (15-14x)/9 = 0

By taking LCM for 15, 5 and 9 which is 45

((45-2x)3 – (4x+10)9 – (15-14x)5)/45 = 0

(135 – 6x – 36x – 90 – 75 + 70x)/45 = 0

(28x – 30)/45 = 0

By cross-multiplying

28x – 30 = 0

28x = 30

x = 30/28

= 15/14

Let us verify the given equation now,

(45-2x)/15 – (4x+10)/5 = (15-14x)/9

By substituting the value of ‘x’ we get,

(45-2(15/14))/15 – (4(15/14) + 10)/5 = (15 – 14(15/14))/9

(45- 15/7)/15 – (30/7 + 10)/5 = (15-15)/9

300/105 – 100/35 = 0

(300-300)/105 = 0

0 = 0

Hence, the given equation is verified.