Solve the equation and also verify your solution:\(9 \frac{1}{4} = y \

1.	Solve the equation and also verify your solution:\(9 \frac{1}{4} = y \,–\, 1 \frac{1}{3}\)
Answer» We have, \(9 \frac{1}{4} = y \,–\, 1 \frac{1}{3}\) \(\frac{37}{4}\) = y – \(\frac{4}{3}\) Upon solving we get, y = \(\frac{37}{4}\) + \(\frac{4}{3}\) By taking LCM for 4 and 3 is 12 y = \(\frac{(37×3)}{12} \)+ \(\frac{(4×4)}{12}\) = \(\frac{111}{12} + \frac{16}{12}\) = \(\frac{(111 + 16)}{12}\) = \(\frac{127}{12}\) ∴ y = \(\frac{127}{12}\)

Solve the equation and also verify your solution:\(9 \frac{1}{4} = y \,–\, 1 \frac{1}{3}\)

Answer»

We have,

\(9 \frac{1}{4} = y \,–\, 1 \frac{1}{3}\)

\(\frac{37}{4}\) = y – \(\frac{4}{3}\)

Upon solving we get,

y = \(\frac{37}{4}\) + \(\frac{4}{3}\)

By taking LCM for 4 and 3 is 12

y = \(\frac{(37×3)}{12} \)+ \(\frac{(4×4)}{12}\)

= \(\frac{111}{12} + \frac{16}{12}\)

= \(\frac{(111 + 16)}{12}\)

= \(\frac{127}{12}\)

∴ y = \(\frac{127}{12}\)