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Solve the equation and also verify your solution:(x + 2) (x + 3) + (x – 3) (x – 2) – 2x(x + 1) = 0 |
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Answer» We have, (x + 2) (x + 3) + (x – 3) (x – 2) – 2x(x + 1) = 0 Upon expansion we get, x2 + 5x + 6 + x2 – 5x +6 – 2x2 – 2x =0 -2x + 12 = 0 By dividing the equation using -2 we get, x – 6 = 0 x = 6 ∴ x = 6 |
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