1.

Solve the equation by transposing the terms and check your result : 3(x-3)=5(2x + 1)

Answer»

3(x – 3)=5(2x+ 1) 

3(x – 3)= 5(2x ÷ 1) 

3x – 9= 10x+5 

3x = 10x + 5 ÷ 9 (transposing – 9) 

3x = 10x + 14

3x – 10x = 14(transposing+ 10 x) – 7x =14 

x = 14/-7 (transposing x ( – 7))

Check 

LHS = 3(x – 3) = 3[( – 2) – 3] = 3x( – 5) = – 15 

RHS = 5(2x + 1) = 5 x [2( – 2) + 1] = 5 x [ – 4 + 1] 

= 5 x ( – 3)= – 15 

∴ LH.S = R.H.S



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