Solve the equation:\(\frac{3x-2}{5} = 4 - (\frac{x+2}{3})\)

1.	Solve the equation:\(\frac{3x-2}{5} = 4 - (\frac{x+2}{3})\)
Answer» \(\frac{3x-2}{5} = 4 - (\frac{x+2}{3})\) ⇒ 3(3x – 2) = 15 × 4 – 5 (x + 2) Multiplying by 15 as LCM of 5 and 3 is 15 ⇒ 9x – 6 = 60 – 5x – 10 ⇒ 9x – 6 = – 5x + 60 – 10 ⇒ 9x – 6 = – 5x + 50 ⇒ 9x + 5x = 50 + 6 On transposing – 6 and – 5x ⇒ 14x = 56 ⇒ 14x/14 = 56/14 On dividing by 14 on both sides ⇒ x = 4

Answer»

\(\frac{3x-2}{5} = 4 - (\frac{x+2}{3})\)

⇒ 3(3x – 2) = 15 × 4 – 5 (x + 2)

Multiplying by 15 as LCM of 5 and 3 is 15

⇒ 9x – 6 = 60 – 5x – 10

⇒ 9x – 6 = – 5x + 60 – 10

⇒ 9x – 6 = – 5x + 50

⇒ 9x + 5x = 50 + 6

On transposing – 6 and – 5x

⇒ 14x = 56

⇒ 14x/14 = 56/14

On dividing by 14 on both sides

⇒ x = 4

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