Solve the equation:\(\frac{x+1}{2} + \frac{x+2}{3} = \frac{2x-5}{7} +

1.	Solve the equation:\(\frac{x+1}{2} + \frac{x+2}{3} = \frac{2x-5}{7} + 9\)
Answer» \(\frac{x+1}{2} + \frac{x+2}{3} = \frac{2x-5}{7} + 9\) 21(x + 1) + 14 (x + 2) = 6(2x – 5) + 9 x 42 Multiplying by 42 as LCM of 2, 3 and 7 is 42 ⇒ 21x + 21 + 14x + 28 = 12x – 30 + 378 ⇒ 21x + 14x + 21 + 28 = 12x – 30 + 378 ⇒ 35x + 49 = 12x + 348 ⇒ 35x – 12x = 348 – 49 On transposing 12x and 49 ⇒ 23x = 299 ⇒ 23x/23 = 299/23 On dividing by 23 on both sides ⇒ x = 13

Solve the equation:\(\frac{x+1}{2} + \frac{x+2}{3} = \frac{2x-5}{7} + 9\)

Answer»

\(\frac{x+1}{2} + \frac{x+2}{3} = \frac{2x-5}{7} + 9\)

21(x + 1) + 14 (x + 2) = 6(2x – 5) + 9 x 42

Multiplying by 42 as LCM of 2, 3 and 7 is 42

⇒ 21x + 21 + 14x + 28 = 12x – 30 + 378

⇒ 21x + 14x + 21 + 28 = 12x – 30 + 378

⇒ 35x + 49 = 12x + 348

⇒ 35x – 12x = 348 – 49

On transposing 12x and 49

⇒ 23x = 299

⇒ 23x/23 = 299/23

On dividing by 23 on both sides

⇒ x = 13