InterviewSolution
Saved Bookmarks
| 1. |
Solve the equation z^3=i |
|
Answer» Solution :`Z^3=i=COS((3pi)/2)+ISIN((3pi)/2)` `=cos(2kpi+PI/2)+isin (2kpi+pi/2)` `=cos(pi(4k+1))/2 +sin(pi(4k+1))/2` `:.z=[cos((4k+1))/2+isin((4k+1)pi)/2]^(1/3) `=cos((4k+1)pi)/6+isin((4k+1)pi)/6` `"where" k=0,1,2.` |
|