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Solve the equation z^7=1 |
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Answer» Solution :`z^7=1=COS 0+ SIN 0` `=cos(0+2kpi+isin 2kpi)` `=cos 2kpi+isin 2kpi` `:.z=(cos 2kpi+isin 2kpi)^(1/7)` `=cos (2kpi)/7)+isin(2kpi)/7)` `"where"k=0,1,2,3,4,5,6` |
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