1.

Solve the equation z^7=1

Answer»

Solution :`z^7=1=COS 0+ SIN 0`
`=cos(0+2kpi+isin 2kpi)`
`=cos 2kpi+isin 2kpi`
`:.z=(cos 2kpi+isin 2kpi)^(1/7)`
`=cos (2kpi)/7)+isin(2kpi)/7)`
`"where"k=0,1,2,3,4,5,6`


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