Solve the equations and check your answers:6 (1 – 4x) + 7 (2 + 5x) =

1.	Solve the equations and check your answers:6 (1 – 4x) + 7 (2 + 5x) = 53
Answer» Given 6 (1 – 4x) + 7 (2 + 5x) = 53 On simplifying the brackets, we get (6 ×1) – (6 × 4x) + (7 × 2) + (7 × 5x) = 53 6 – 24x + 14 + 35x = 53 6 + 14 + 35x – 24x = 53 20 + 11x = 53 Subtracting 20 from both sides, we get 20 + 11x – 20 = 53 – 20 11x = 33 Dividing both sides by 11, we get 11x/11 = 33/11 x = 3 Verification: Substituting x = 3 in LHS, we get 6(1 – 4 × 3) + 7(2 + 5 × 3) = 53 6(1 – 12) + 7(2 + 15) = 53 6(-11) + 7(17) = 53 – 66 + 119 = 53 53 = 53 Therefore LHS = RHS Hence, verified.

Solve the equations and check your answers:6 (1 – 4x) + 7 (2 + 5x) = 53

Answer»

Given 6 (1 – 4x) + 7 (2 + 5x) = 53

On simplifying the brackets, we get

(6 ×1) – (6 × 4x) + (7 × 2) + (7 × 5x) = 53

6 – 24x + 14 + 35x = 53

6 + 14 + 35x – 24x = 53

20 + 11x = 53

Subtracting 20 from both sides, we get 20 + 11x – 20 = 53 – 20

11x = 33

Dividing both sides by 11, we get

11x/11 = 33/11

x = 3

Verification:

Substituting x = 3 in LHS, we get

6(1 – 4 × 3) + 7(2 + 5 × 3) = 53

6(1 – 12) + 7(2 + 15) = 53

6(-11) + 7(17) = 53

– 66 + 119 = 53

53 = 53

Therefore LHS = RHS

Hence, verified.