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Solve the following differential equations.dy/dx=e^y |
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Answer» Solution :`dy/dx=E^yrArre^(-y)dy=dx` Integrating we GET `inte^(-y)dy=intdx` `RARR e^(-y)/-1=x+C rArr -e^(-y)+x+C` `rArrx+e^(-y)+C=0` |
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