1.

Solve the following differential equations.dy/dx=e^y

Answer»

Solution :`dy/dx=E^yrArre^(-y)dy=dx`
Integrating we GET `inte^(-y)dy=intdx`
`RARR e^(-y)/-1=x+C rArr -e^(-y)+x+C`
`rArrx+e^(-y)+C=0`


Discussion

No Comment Found

Related InterviewSolutions