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Solve the following equations : i. 4(x + 12) = 8 ii. 3y + 4 = 5y – 6 |
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Answer» i. 4(x + 12) = 8 ∴ 4x + 48 = 8 ∴ 4x + 48 – 48 = 8 – 48 ….(Subtracting 48 from both sides) ∴ 4x = -40 ∴ \(x = \frac{-40}{4}\) ∴ x = -10 ii. 3y + 4 = 5y – 6 ∴ 3y + 4 + 6 = 5y – 6 + 6 ….(Adding 6 on both sides) ∴ 3y + 10 = 5y ∴ 3y + 10 – 3y = 5y – 3y ….(Subtracting 3y from both sides) ∴ 10 = 2y ∴ 2y = 10 ∴ y = 10/2 ∴ y = 5 |
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