InterviewSolution
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Solve the following equations:i. y – 5 = 1 ii. 8 = t + 5 iii. 4x = 52 iv. 19 = m – 4 |
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Answer» i. y – 5 = 1 ∴ y – 5 + 5 = 1 + 5 …. (Adding 5 to both sides) ∴ y + 0 = 6 ∴ y = 6 ii. 8 = t + 5 ∴ 8 – 5 = t + 5 – 5 ……(Subtracting 5 from both sides) ∴ 8 + (-5) = t + 0 ∴ 3 = t ∴ t = 3 iii. 4x = 52 ∴ \(\cfrac{4x}{4} = \cfrac{52}{4}\) …. (Dividing both sides by 4) ∴ 1x = 13 ∴ x = 13 iv. 19 = m -4 ∴ 19 + 4 = m – 4 + 4 …. (Adding 4 to both sides) ∴ 23 = m + 0 ∴ m = 23 |
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