InterviewSolution
Saved Bookmarks
| 1. |
Solve the following pair of linear equations 2(ax-by) + (a + 4b) = 0 2(bx + ay) + (b-40 = 0 |
|
Answer» The given equations may be written as ` 2ax - 2by = -a - 4b " " `… (i) ` 2bx + 2ay = 4a - b " " `… (ii) Multiplying (i) by a and (ii) by b and adding , we get ` ( 2 a ^(2) + 2 b ^(2)) x = ( - a ^(2) - b ^(2))` ` rArr 2 (a ^(2) + b (2)) x = - (a ^(2) + b ^(2)) rArr x = (-1)/(2)` Putting ` x = (-1)/(2) ` in (i), we get ` 2a xx ((-1)/(2)) - 2 by = - a - 4 b ` ` rArr - a - 2by = - a - 4 b ` ` rArr 2by = 4 b rArr y = ( 4 b )/( 2 b ) = 2 ` Hence, ` x = (-1)/(2) and y = 2 ` |
|