1.

Solve the following pair of linear equations by substitution method :3x + 2y - 7 = 04x + y - 6 = 0

Answer»

3x + 2y - 7 = 0  .......(i)

4x + y - 6 = 0   ..........(ii)

From eqn (ii)

4x + y - 6 = 0

y = 6 - 4x

Value of y put in eqn. (i) 

3x + 2y - 7= 0 

3x + 2(6- 4x) - 7 = 0 

3x + 12 - 8x - 7 = 0 

5 - 5x = 0 

5x = 5 

x = 1

Substitute the value of x in eq (ii) to get value of y,

4x + y - 6 = 0 

4(1) + y - 6 = 0 

4 + y - 6 = 0 

y - 2 = 0

y = 2

Hence, values of x and y are 1 and 2 respectively.



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