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Solve the following pair of linear equations by substitution method :3x + 2y - 7 = 04x + y - 6 = 0 |
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Answer» 3x + 2y - 7 = 0 .......(i) 4x + y - 6 = 0 ..........(ii) From eqn (ii) 4x + y - 6 = 0 y = 6 - 4x Value of y put in eqn. (i) 3x + 2y - 7= 0 3x + 2(6- 4x) - 7 = 0 3x + 12 - 8x - 7 = 0 5 - 5x = 0 5x = 5 x = 1 Substitute the value of x in eq (ii) to get value of y, 4x + y - 6 = 0 4(1) + y - 6 = 0 4 + y - 6 = 0 y - 2 = 0 y = 2 Hence, values of x and y are 1 and 2 respectively. |
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