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Solve the following quadratic equation for `x:4x^2 + 4bx – (a^2-b^2) = 0` |
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Answer» Correct Answer - `x=(-(a+b))/(2)" or "x=(a-b)/(2)` `4x^(2)+4bx+(b^(2)-a^(2))=0implies4x^(2)+2(b+a)x+2(b-a)x+(b^(2)-a^(2))=0.` |
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