1.

Solve the following quadratic equation for `x:4x^2 + 4bx – (a^2-b^2) = 0`

Answer» Correct Answer - `x=(-(a+b))/(2)" or "x=(a-b)/(2)`
`4x^(2)+4bx+(b^(2)-a^(2))=0implies4x^(2)+2(b+a)x+2(b-a)x+(b^(2)-a^(2))=0.`


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