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Solve the following quadratic equations by factorization:\(x^{2}+2ab=(2a+b)x\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(x^{2}+2ab=(2a+b)x\) ⇒ x2 – (2a + b)x + 2ab = 0 ⇒ x2 – 2ax – bx + 2ab = 0 ⇒ x(x – 2a) – b(x – 2a) = 0 ⇒ (x – b)(x – 2a) = 0 ⇒ x = b, 2a |
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