1.

Solve the following quadratic equations by factorization:\(\frac{4}{x}-3=\frac{5}{2x+3},x\neq0,-\frac{3}{2}\)

Answer»

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(\frac{4}{x}-3=\frac{5}{2x+3},x\neq0,-\frac{3}{2}\)

⇒ (4 – 3x)(2x + 3) = 5x 

⇒ 8x + 12 – 6x2 – 9x = 5x 

⇒ 6x2 + 6x – 12 = 0 

⇒ x2 + x – 2 = 0 

⇒ x2 + 2x – x – 2 = 0 

⇒ x(x + 2) – (x + 2) = 0 

⇒ (x – 1)(x + 2) = 0 

⇒ x = 1, - 2



Discussion

No Comment Found