1.

Solve the following quadratic equations by factorization:\(x^2-x-a(a+1)=0\)

Answer»

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(x^2-x-a(a+1)=0\)

⇒ x2 – a2 – x – a = 0 

⇒ (x + a)(x – a) – 1(x + a) = 0 

⇒ (x + a)(x – a – 1) = 0 

⇒ x = -a, a + 1



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