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Solve the following quadratic equations by factorization:\(x^2-x-a(a+1)=0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(x^2-x-a(a+1)=0\) ⇒ x2 – a2 – x – a = 0 ⇒ (x + a)(x – a) – 1(x + a) = 0 ⇒ (x + a)(x – a – 1) = 0 ⇒ x = -a, a + 1 |
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