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Solve the following quadratic equations by factorization:\(3x^{2}-14x-5=0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(3x^{2}-14x-5=0\) ⇒ 3x2 – 15x + x – 5 = 0 ⇒ 3x(x – 5) + 1(x – 5) = 0 ⇒ (3x + 1)(x – 5) = 0 ⇒ x = 5, -1/3 |
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