1.

Solve the following quadratic equations by factorization:\(3x^{2}-14x-5=0\)

Answer»

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(3x^{2}-14x-5=0\)

⇒ 3x2 – 15x + x – 5 = 0 

⇒ 3x(x – 5) + 1(x – 5) = 0 

⇒ (3x + 1)(x – 5) = 0 

⇒ x = 5, -1/3



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