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Solve the following quadratic equations by factorization:\(\frac{16}{x}-1=\frac{15}{x+1};x\neq0,-1\)

Answer»

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(\frac{16}{x}-1=\frac{15}{x+1};x\neq0,-1\)

⇒ (16 – x)(x + 1) = 15x 

⇒ -x2 – x + 16x + 16 = 15x 

⇒ x2 = 16

⇒ x = 4



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