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Solve the following quadratic equations by factorization:\(\frac{16}{x}-1=\frac{15}{x+1};x\neq0,-1\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\frac{16}{x}-1=\frac{15}{x+1};x\neq0,-1\) ⇒ (16 – x)(x + 1) = 15x ⇒ -x2 – x + 16x + 16 = 15x ⇒ x2 = 16 ⇒ x = 4 |
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