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Solve the following quadratic equations by factorization:\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{5}{6},x\neq1,-1\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{5}{6},x\neq1,-1\) ⇒ 6((x + 1)2 - (x – 1)2) = 5(x2 – 1) ⇒ 6 × 4x = 5x2 – 5 ⇒ 5x2 – 24x – 5 = 0 ⇒ 5x2 – 25x + x – 5 = 0 ⇒ 5x(x – 5) + 1(x-5) = 0 ⇒ (5x + 1)(x – 5) = 0 ⇒ x = 5, -1/5 |
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