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InterviewSolution
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Solve the following quadratic equations by factorization:\(\frac{1}{x-2}+\frac{2}{x-1}=\frac{6}{x},x\neq0\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\frac{1}{x-2}+\frac{2}{x-1}=\frac{6}{x},x\neq0\) ⇒ x(x – 1 + 2x – 4) = 6(x2 -3x + 2) ⇒ 3x2 - 5x = 6x2 – 18x + 12 ⇒ 3x2 - 13x + 12 = 0 ⇒ 3x2 - 9x - 4x + 12 = 0 ⇒ 3x(x - 3) -4(x – 3) = 0 ⇒ (3x – 4)(x – 3) = 0 ⇒ x = 4/3, 3 |
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