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Solve the following quadratic equations by factorization:\(\frac{x+3}{x+2}=\frac{3x-7}{2x-3}\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\frac{x+3}{x+2}=\frac{3x-7}{2x-3}\) ⇒ 2x2 – 9 + 3x = 3x2 – 14 –x ⇒ x2 – 4x – 5 = 0 ⇒ x2 – 5x + x – 5 = 0 ⇒ (x – 5)(x + 1) = 0 ⇒ x = -1, 5 |
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