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Solve the following quadratic equations by factorization:\(3x^2-2\sqrt{6}x+2=0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(3x^2-2\sqrt{6}x+2=0\) ⇒ (√3x)2 – 2√6x + (√2)2 = 0 ⇒ (√3x - √2)2 = 0 ⇒ x \(\frac{\sqrt{2}}{\sqrt{3}},\)\(\frac{\sqrt{2}}{\sqrt{3}}\) |
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