1.

Solve the following quadratic equations by factorization:\(3x^2-2\sqrt{6}x+2=0\)

Answer»

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(3x^2-2\sqrt{6}x+2=0\)

⇒ (√3x)2 – 2√6x + (√2)2 = 0 

⇒ (√3x - √2)2 = 0

⇒ x \(\frac{\sqrt{2}}{\sqrt{3}},\)\(\frac{\sqrt{2}}{\sqrt{3}}\)



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