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Solve the following quadratic equations by factorization:\(a^2b^2x^2+b^2x-a^2x-1=0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(a^2b^2x^2+b^2x-a^2x-1=0\) ⇒ b2x(a2x + 1) – (a2x + 1) = 0 ⇒ (b2x – 1)(a2x + 1) = 0 ⇒ x = -1/a2, 1/b2 |
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