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Solve the following quadratic equations by factorization:\(x-\frac{1}{x-3}=3,x\neq0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(x-\frac{1}{x-3}=3,x\neq0\) ⇒ x2 – 3x – 1 = 3x – 9 ⇒ x2 – 6x + 8 = 0 ⇒ x2 – 4x – 2x + 8 = 0 ⇒ x(x – 4) – 2(x – 4) = 0 ⇒ (x – 2)(x – 4) = 0 ⇒ x = 2, 4 |
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