Solve the following system of equations:0.4x + 0.3y = 1.7; 0.7x – 0

1.	Solve the following system of equations:0.4x + 0.3y = 1.7; 0.7x – 0.2y = 0.8
Answer» The given pair of equations are: 0.4x + 0.3y = 1.7 0.7x – 0.2y = 0.8 Let’s, multiply LHS and RHS by 10 to make the coefficients as an integer 4x + 3y = 17 …………(i) 7x – 2y = 8 …………..(ii) From (ii) 7x – 2y = 8 x = \(\frac{(8 + 2y)}{7}\)…………(iii) Now, substituting x in equation (i) we get, ⇒ 4[\(\frac{(8 + 2y)}{7}\)] + 3y = 17 ⇒ 32 + 8y + 21y = (17 x 7) ⇒ 29y = 87 ⇒ y = 3 Next, putting the value of y in the equation (iii) we get, ⇒ x = \(\frac{(8 + 2(3))}{7}\) ⇒ x = \(\frac{14}{7}\) ∴ x = 2 Thus, the value of x and y is found to be 2 and 3 respectively.

Solve the following system of equations:0.4x + 0.3y = 1.7; 0.7x – 0.2y = 0.8

Answer»

The given pair of equations are:

0.4x + 0.3y = 1.7

0.7x – 0.2y = 0.8

Let’s, multiply LHS and RHS by 10 to make the coefficients as an integer

4x + 3y = 17 …………(i)

7x – 2y = 8 …………..(ii)

From (ii)

7x – 2y = 8

x = \(\frac{(8 + 2y)}{7}\)…………(iii)

Now, substituting x in equation (i) we get,

⇒ 4[\(\frac{(8 + 2y)}{7}\)] + 3y = 17

⇒ 32 + 8y + 21y = (17 x 7)

⇒ 29y = 87

⇒ y = 3

Next, putting the value of y in the equation (iii) we get,

⇒ x = \(\frac{(8 + 2(3))}{7}\)

⇒ x = \(\frac{14}{7}\)

∴ x = 2

Thus, the value of x and y is found to be 2 and 3 respectively.