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Solve the following system of equations:2/x + 3/y = 9/xy 4/x + 9/y = 21/xy |
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Answer» Taking LCM for both the given equations, we have (2y + 3x)/ xy = 9/xy ⇒ 3x + 2y = 9………. (i) (4y + 9x)/ xy = 21/xy ⇒ 9x + 4y = 21………(ii) Performing (ii) – (i) x 2 ⇒ 9x + 4y – 2(3x + 2y) = 21 – (9×2) ⇒ 3x = 3 ⇒ x = 1 Using x = 1 in (i), we find y 3(1) + 2y = 9 ⇒ y = \(\frac{6}{2}\) ⇒ y = 3 Thus, the solution for the given set of equations is x = 1 and y = 3. |
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