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Solve the following systems of equations:\(\frac{10}{x-y}\)+\(\frac{2}{x-y}\) = 4\(\frac{15}{x+y}\) - \(\frac{9}{x-y}\) = - 2 |
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Answer» \(\frac{10}{x-y}\)+\(\frac{2}{x-y}\) = 4 \(\frac{15}{x+y}\) - \(\frac{9}{x-y}\) = - 2 Multiplying eq1 by 9 and eq2 by 2 and adding ⇒ 120/(x + y) = 32 ⇒ x + y = 15/4 ---- (1) Multiplying eq1 by 3 and eq2 by 2 and subtracting ⇒ 24/(x – y) = 16 ⇒ x – y = 3/2 ---- (2) Adding (1) and (2) ⇒ 2x = 21/4 ⇒ x = 21/8 Thus, 21/8 – y = 3/2 ⇒ y = 9/8 |
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