Solve the following systems of equations:x + 2y = \(\frac{3}{2}\)2x +

1.	Solve the following systems of equations:x + 2y = \(\frac{3}{2}\)2x + y = \(\frac{3}{2}\)
Answer» x + 2y = \(\frac{3}{2}\) ⇒ 2x + 4y = 3 …(i) 2x + y = \(\frac{3}{2}\) ⇒ 4x + 2y = 3 …(ii) Multiplying eq2 by 2 and subtracting from eq1 2x + 4y – 8x – 4y = 3 – 6 ⇒ - 6x = - 3 ⇒ x = 1/2 Thus, 2 × 1/2 + 4y = 3 ⇒ y = 1/2

Solve the following systems of equations:x + 2y = \(\frac{3}{2}\)2x + y = \(\frac{3}{2}\)

Answer»

x + 2y = \(\frac{3}{2}\)

⇒ 2x + 4y = 3 …(i)

2x + y = \(\frac{3}{2}\)

⇒ 4x + 2y = 3 …(ii)

Multiplying eq2 by 2 and subtracting from eq1

2x + 4y – 8x – 4y = 3 – 6

⇒ - 6x = - 3

⇒ x = 1/2

Thus,

2 × 1/2 + 4y = 3

⇒ y = 1/2