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Solve the following systems of linear inequalities graphically : x + y gt 1 , 3x - y lt 3, x- 3y + 3 gt 0. |
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Answer» Solution : `x + y GT 1 `3x-y lt 3` Step-2 : Let us CONSIDER the point (0,0) that does not lie on these Putting x=0,y=0 in the inequations we get, thus (0,0) satisfies 3x-y `lt`3 and x-3y + 3 `gt`0 but does satisfy x + y `gt` 1. `therefore` The shaded REGION is the solutions region. |
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