1.

Solve the folowing (3 marks each)The sum of the squares of two consecutive odd positive integers is 290. Find the numbers

Answer»

let noms be x ans x+2x²+(x+2)²=290x²+x²+4x+4=2902x²+4x+4-290=02x²+4x-286=0x²+2x-143=0x²+13x-11x-143=0x(x+13)-11(x+13)=0(x-11)(x+13)=0x=11,-13

required no.s are 11 and 13



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