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Solve the Given Differential Equation by Variation of Parameters. xy'' − 4y' = x4 |
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Answer» The general solution of differential equationxy'' − 4y' = x4by variation of parameters isy =\(c_1\)+ \(c_2\)x5 -1/25x5+ 1/5 x5lnx. We will be solving this by finding thehomogeneous andcomplementary solutions of the equation. |
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