1.

Solve the quadratic equation:- x + 1/x = 17/4

Answer»

\(x\) + \(\frac{1}{x}\) = \(\frac{17}{4}\)

\(​​\frac{x^2 + 1}{x}\) = \(\frac{17}{4}\)

\(x^2 - \frac{17x}{4} + 1\)\(0\)

⇒ \( 4x^2 - 17x + 4 = 0\)

\(4x^2 - 16x - x + 4 = 0\)

\(4x(x - 4) - 1(x - 4) = 0\)

\((4x - 1) (x - 4) = 0\)

∴ \( x = \frac{1}{4}, 4\)



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