InterviewSolution
Saved Bookmarks
| 1. |
Solve the quadratic equation:x2 – (3√2 + 2i)x + 6√2i = 0 |
|
Answer» Given as x2 – (3√2 + 2i)x + 6√2i = 0 x2 – (3√2x + 2ix) + 6√2i = 0 x2 – 3√2x – 2ix + 6√2i = 0 x(x – 3√2) – 2i(x – 3√2) = 0 (x – 3√2) (x – 2i) = 0 (x – 3√2) = 0 or (x – 2i) = 0 x = 3√2 or x = 2i ∴ The roots of the given equation are 3√2, 2i |
|