InterviewSolution
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InterviewSolution
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Solve the quadratic equation:x2 + 4ix – 4 = 0 |
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Answer» Given as x2 + 4ix – 4 = 0 x2 + 4ix + 4(–1) = 0 [as we know, i2 = –1] Therefore by substituting –1 = i2 in the above equation, we get x2 + 4ix + 4i2 = 0 x2 + 2ix + 2ix + 4i2 = 0 x(x + 2i) + 2i(x + 2i) = 0 (x + 2i) (x + 2i) = 0 (x + 2i)2 = 0 x + 2i = 0 x = –2i, -2i Therefore, the roots of the given equation are –2i, –2i |
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