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Solve the quadratic equations by factorization method only:x2 + 2x + 2 = 0 |
Answer» Given as x2 + 2x + 2 = 0 x2 + 2x + 1 + 1 = 0 x2 + 2(x)(1) + 12 + 1 = 0 (x + 1)2 + 1 = 0 [∵ (a + b)2 = a2 + 2ab + b2] As we know, i2 = –1 ⇒ 1 = –i2 On substituting 1 = –i2 in the above equation, we get (x + 1)2 + (–i2) = 0 (x + 1)2 – i2 = 0 (x + 1)2 – (i)2 = 0 [On using the formula, a2 – b2 = (a + b) (a – b)] (x + 1 + i) (x + 1 – i) = 0 x + 1 + i = 0 or x + 1 – i = 0 x = –1 – i or x = –1 + i x = -1 ± i ∴ The roots of the given equation are -1 ± i |
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